The OpenFileDialog component allows users to browse the folders of their computer or any computer on the network and select one or more files to open. The dialog box. How to view Excel Files with OpenFileDialog? C# / C Sharp. You need to get the selected file(s) from the OpenFileDialog. OpenFileDialog.Filter = 'xml files.

You need to get the selected file(s) from the OpenFileDialog. You can do this with the property.

You also may want to consider doing a check on the return value from the ShowDialog method. It returns a DialogResult enum that tells you what was clicked. This way you can avoid trying to process a list of files that doesn't exist because your user clicked Cancel on the dialog:) From what you describe, it sounds like you know how make it open in Excel, do you still need any help with that? Finally, your final sentence there confuses me. What do you mean? Well, what files do you actually want? If you actually do want everything, go ahead and use *. Why You Lying. * and that's fine, but you should probably ask yourself if you want users trying to open everything with excel.

Download Extras Ricky Gervais Rapidshare more. The filter is there to make it easier for the user to find the files they want (or can) open and to hide things that they shouldn't be concerned with. Ascharya Deepak Tv Serial on this page. Excel only opens certain kinds of files. If you try to open a file, you can see the kinds of files it supports.

It also has *.* on the list and the user can choose this. If your program is causing Excel to open files, you might want to consider cloning their filters. Or, if you're happy with *.*, just go with that. Ultimately it's up to you:D.

I have tried this code it would open the file dialog to the correct location and there is only one xml file which needs to selected ( where i need to select it and click on open ) instead of selecting the file and click open to process the file is there any way to disable the open button on open file dialog. Here my xml file changes everyday. I have given *.xml but gives me a error Illegal characters in path. My file format is this. Lborough vehicles_in 2014-06-05.xml == this changes everyday according to date. Without clicking on open how to select the file.

Is there any reason that you can't use to get all files in a directory and use to get the file? Why do you want to do this with a FileDialog, if you don't want the FileDialog? Update: //Load Schema and Vehicle_In XML file tblVehicles.ReadXmlSchema(Path.Combine(applicationFolder, 'vehicles_in.xsd')); // Get all XML files from the files directory string[] filePaths = Directory.GetFiles(@'files ', '*.xml', SearchOption.AllDirectories); // Read the first XML file in the files directory tblVehicles.ReadXml(filePaths[0]); Is this what you asked for?